Optimal. Leaf size=233 \[ -\frac {a f}{2 e^2 \left (f+\frac {e}{x}\right )^2}+\frac {a}{e^2 \left (f+\frac {e}{x}\right )}-\frac {b d f \cos \left (c+\frac {d}{x}\right )}{2 e^3 \left (f+\frac {e}{x}\right )}-\frac {b d \cos \left (c-\frac {d f}{e}\right ) \text {Ci}\left (d \left (\frac {f}{e}+\frac {1}{x}\right )\right )}{e^3}-\frac {b d^2 f \text {Ci}\left (d \left (\frac {f}{e}+\frac {1}{x}\right )\right ) \sin \left (c-\frac {d f}{e}\right )}{2 e^4}-\frac {b f \sin \left (c+\frac {d}{x}\right )}{2 e^2 \left (f+\frac {e}{x}\right )^2}+\frac {b \sin \left (c+\frac {d}{x}\right )}{e^2 \left (f+\frac {e}{x}\right )}-\frac {b d^2 f \cos \left (c-\frac {d f}{e}\right ) \text {Si}\left (d \left (\frac {f}{e}+\frac {1}{x}\right )\right )}{2 e^4}+\frac {b d \sin \left (c-\frac {d f}{e}\right ) \text {Si}\left (d \left (\frac {f}{e}+\frac {1}{x}\right )\right )}{e^3} \]
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Rubi [A]
time = 0.30, antiderivative size = 233, normalized size of antiderivative = 1.00, number of steps
used = 15, number of rules used = 6, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.300, Rules used = {3512, 3398,
3378, 3384, 3380, 3383} \begin {gather*} \frac {a}{e^2 \left (\frac {e}{x}+f\right )}-\frac {a f}{2 e^2 \left (\frac {e}{x}+f\right )^2}-\frac {b d^2 f \sin \left (c-\frac {d f}{e}\right ) \text {CosIntegral}\left (d \left (\frac {f}{e}+\frac {1}{x}\right )\right )}{2 e^4}-\frac {b d \cos \left (c-\frac {d f}{e}\right ) \text {CosIntegral}\left (d \left (\frac {f}{e}+\frac {1}{x}\right )\right )}{e^3}-\frac {b d^2 f \cos \left (c-\frac {d f}{e}\right ) \text {Si}\left (d \left (\frac {f}{e}+\frac {1}{x}\right )\right )}{2 e^4}+\frac {b d \sin \left (c-\frac {d f}{e}\right ) \text {Si}\left (d \left (\frac {f}{e}+\frac {1}{x}\right )\right )}{e^3}-\frac {b d f \cos \left (c+\frac {d}{x}\right )}{2 e^3 \left (\frac {e}{x}+f\right )}+\frac {b \sin \left (c+\frac {d}{x}\right )}{e^2 \left (\frac {e}{x}+f\right )}-\frac {b f \sin \left (c+\frac {d}{x}\right )}{2 e^2 \left (\frac {e}{x}+f\right )^2} \end {gather*}
Antiderivative was successfully verified.
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Rule 3378
Rule 3380
Rule 3383
Rule 3384
Rule 3398
Rule 3512
Rubi steps
\begin {align*} \int \frac {a+b \sin \left (c+\frac {d}{x}\right )}{(e+f x)^3} \, dx &=-\text {Subst}\left (\int \left (-\frac {f (a+b \sin (c+d x))}{e (f+e x)^3}+\frac {a+b \sin (c+d x)}{e (f+e x)^2}\right ) \, dx,x,\frac {1}{x}\right )\\ &=-\frac {\text {Subst}\left (\int \frac {a+b \sin (c+d x)}{(f+e x)^2} \, dx,x,\frac {1}{x}\right )}{e}+\frac {f \text {Subst}\left (\int \frac {a+b \sin (c+d x)}{(f+e x)^3} \, dx,x,\frac {1}{x}\right )}{e}\\ &=-\frac {\text {Subst}\left (\int \left (\frac {a}{(f+e x)^2}+\frac {b \sin (c+d x)}{(f+e x)^2}\right ) \, dx,x,\frac {1}{x}\right )}{e}+\frac {f \text {Subst}\left (\int \left (\frac {a}{(f+e x)^3}+\frac {b \sin (c+d x)}{(f+e x)^3}\right ) \, dx,x,\frac {1}{x}\right )}{e}\\ &=-\frac {a f}{2 e^2 \left (f+\frac {e}{x}\right )^2}+\frac {a}{e^2 \left (f+\frac {e}{x}\right )}-\frac {b \text {Subst}\left (\int \frac {\sin (c+d x)}{(f+e x)^2} \, dx,x,\frac {1}{x}\right )}{e}+\frac {(b f) \text {Subst}\left (\int \frac {\sin (c+d x)}{(f+e x)^3} \, dx,x,\frac {1}{x}\right )}{e}\\ &=-\frac {a f}{2 e^2 \left (f+\frac {e}{x}\right )^2}+\frac {a}{e^2 \left (f+\frac {e}{x}\right )}-\frac {b f \sin \left (c+\frac {d}{x}\right )}{2 e^2 \left (f+\frac {e}{x}\right )^2}+\frac {b \sin \left (c+\frac {d}{x}\right )}{e^2 \left (f+\frac {e}{x}\right )}-\frac {(b d) \text {Subst}\left (\int \frac {\cos (c+d x)}{f+e x} \, dx,x,\frac {1}{x}\right )}{e^2}+\frac {(b d f) \text {Subst}\left (\int \frac {\cos (c+d x)}{(f+e x)^2} \, dx,x,\frac {1}{x}\right )}{2 e^2}\\ &=-\frac {a f}{2 e^2 \left (f+\frac {e}{x}\right )^2}+\frac {a}{e^2 \left (f+\frac {e}{x}\right )}-\frac {b d f \cos \left (c+\frac {d}{x}\right )}{2 e^3 \left (f+\frac {e}{x}\right )}-\frac {b f \sin \left (c+\frac {d}{x}\right )}{2 e^2 \left (f+\frac {e}{x}\right )^2}+\frac {b \sin \left (c+\frac {d}{x}\right )}{e^2 \left (f+\frac {e}{x}\right )}-\frac {\left (b d^2 f\right ) \text {Subst}\left (\int \frac {\sin (c+d x)}{f+e x} \, dx,x,\frac {1}{x}\right )}{2 e^3}-\frac {\left (b d \cos \left (c-\frac {d f}{e}\right )\right ) \text {Subst}\left (\int \frac {\cos \left (\frac {d f}{e}+d x\right )}{f+e x} \, dx,x,\frac {1}{x}\right )}{e^2}+\frac {\left (b d \sin \left (c-\frac {d f}{e}\right )\right ) \text {Subst}\left (\int \frac {\sin \left (\frac {d f}{e}+d x\right )}{f+e x} \, dx,x,\frac {1}{x}\right )}{e^2}\\ &=-\frac {a f}{2 e^2 \left (f+\frac {e}{x}\right )^2}+\frac {a}{e^2 \left (f+\frac {e}{x}\right )}-\frac {b d f \cos \left (c+\frac {d}{x}\right )}{2 e^3 \left (f+\frac {e}{x}\right )}-\frac {b d \cos \left (c-\frac {d f}{e}\right ) \text {Ci}\left (\frac {d \left (f+\frac {e}{x}\right )}{e}\right )}{e^3}-\frac {b f \sin \left (c+\frac {d}{x}\right )}{2 e^2 \left (f+\frac {e}{x}\right )^2}+\frac {b \sin \left (c+\frac {d}{x}\right )}{e^2 \left (f+\frac {e}{x}\right )}+\frac {b d \sin \left (c-\frac {d f}{e}\right ) \text {Si}\left (\frac {d \left (f+\frac {e}{x}\right )}{e}\right )}{e^3}-\frac {\left (b d^2 f \cos \left (c-\frac {d f}{e}\right )\right ) \text {Subst}\left (\int \frac {\sin \left (\frac {d f}{e}+d x\right )}{f+e x} \, dx,x,\frac {1}{x}\right )}{2 e^3}-\frac {\left (b d^2 f \sin \left (c-\frac {d f}{e}\right )\right ) \text {Subst}\left (\int \frac {\cos \left (\frac {d f}{e}+d x\right )}{f+e x} \, dx,x,\frac {1}{x}\right )}{2 e^3}\\ &=-\frac {a f}{2 e^2 \left (f+\frac {e}{x}\right )^2}+\frac {a}{e^2 \left (f+\frac {e}{x}\right )}-\frac {b d f \cos \left (c+\frac {d}{x}\right )}{2 e^3 \left (f+\frac {e}{x}\right )}-\frac {b d \cos \left (c-\frac {d f}{e}\right ) \text {Ci}\left (\frac {d \left (f+\frac {e}{x}\right )}{e}\right )}{e^3}-\frac {b d^2 f \text {Ci}\left (\frac {d \left (f+\frac {e}{x}\right )}{e}\right ) \sin \left (c-\frac {d f}{e}\right )}{2 e^4}-\frac {b f \sin \left (c+\frac {d}{x}\right )}{2 e^2 \left (f+\frac {e}{x}\right )^2}+\frac {b \sin \left (c+\frac {d}{x}\right )}{e^2 \left (f+\frac {e}{x}\right )}-\frac {b d^2 f \cos \left (c-\frac {d f}{e}\right ) \text {Si}\left (\frac {d \left (f+\frac {e}{x}\right )}{e}\right )}{2 e^4}+\frac {b d \sin \left (c-\frac {d f}{e}\right ) \text {Si}\left (\frac {d \left (f+\frac {e}{x}\right )}{e}\right )}{e^3}\\ \end {align*}
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Mathematica [A]
time = 1.22, size = 151, normalized size = 0.65 \begin {gather*} -\frac {b d \text {Ci}\left (d \left (\frac {f}{e}+\frac {1}{x}\right )\right ) \left (2 e \cos \left (c-\frac {d f}{e}\right )+d f \sin \left (c-\frac {d f}{e}\right )\right )+\frac {e \left (a e^3+b d f^2 x (e+f x) \cos \left (c+\frac {d}{x}\right )-b e f x (2 e+f x) \sin \left (c+\frac {d}{x}\right )\right )}{f (e+f x)^2}+b d \left (d f \cos \left (c-\frac {d f}{e}\right )-2 e \sin \left (c-\frac {d f}{e}\right )\right ) \text {Si}\left (d \left (\frac {f}{e}+\frac {1}{x}\right )\right )}{2 e^4} \end {gather*}
Antiderivative was successfully verified.
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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(541\) vs.
\(2(223)=446\).
time = 0.12, size = 542, normalized size = 2.33
method | result | size |
risch | \(-\frac {a}{2 f \left (f x +e \right )^{2}}+\frac {i b \,d^{2} {\mathrm e}^{-\frac {i \left (c e -d f \right )}{e}} \expIntegral \left (1, \frac {i d}{x}+i c -\frac {i \left (c e -d f \right )}{e}\right ) f}{4 e^{4}}+\frac {b d \,{\mathrm e}^{-\frac {i \left (c e -d f \right )}{e}} \expIntegral \left (1, \frac {i d}{x}+i c -\frac {i \left (c e -d f \right )}{e}\right )}{2 e^{3}}+\frac {b d \,{\mathrm e}^{\frac {i \left (c e -d f \right )}{e}} \expIntegral \left (1, -\frac {i d}{x}-i c -\frac {-i c e +i d f}{e}\right )}{2 e^{3}}-\frac {i b \,d^{2} f \,{\mathrm e}^{\frac {i \left (c e -d f \right )}{e}} \expIntegral \left (1, -\frac {i d}{x}-i c -\frac {-i c e +i d f}{e}\right )}{4 e^{4}}+\frac {i b x \left (2 i d^{3} f^{4} x^{3}+6 i d^{3} e \,f^{3} x^{2}+6 i d^{3} e^{2} f^{2} x +2 i d^{3} e^{3} f \right ) \cos \left (\frac {c x +d}{x}\right )}{4 e^{3} \left (f x +e \right )^{2} \left (d^{2} x^{2} f^{2}+2 d^{2} e f x +d^{2} e^{2}\right )}-\frac {b x \left (-2 d^{2} f^{3} x^{3}-8 d^{2} e \,f^{2} x^{2}-10 d^{2} e^{2} f x -4 d^{2} e^{3}\right ) \sin \left (\frac {c x +d}{x}\right )}{4 e^{2} \left (f x +e \right )^{2} \left (d^{2} x^{2} f^{2}+2 d^{2} e f x +d^{2} e^{2}\right )}\) | \(423\) |
derivativedivides | \(-d \left (-\frac {a}{e^{2} \left (-c e +d f +e \left (c +\frac {d}{x}\right )\right )}-\frac {\left (c e -d f \right ) a}{2 e^{2} \left (-c e +d f +e \left (c +\frac {d}{x}\right )\right )^{2}}+\frac {\left (c e -d f \right ) b \left (-\frac {\sin \left (c +\frac {d}{x}\right )}{2 \left (-c e +d f +e \left (c +\frac {d}{x}\right )\right )^{2} e}+\frac {-\frac {\cos \left (c +\frac {d}{x}\right )}{\left (-c e +d f +e \left (c +\frac {d}{x}\right )\right ) e}-\frac {-\frac {\sinIntegral \left (-\frac {d}{x}-c -\frac {-c e +d f}{e}\right ) \cos \left (\frac {-c e +d f}{e}\right )}{e}-\frac {\cosineIntegral \left (\frac {d}{x}+c +\frac {-c e +d f}{e}\right ) \sin \left (\frac {-c e +d f}{e}\right )}{e}}{e}}{2 e}\right )}{e}+\frac {b \left (-\frac {\sin \left (c +\frac {d}{x}\right )}{\left (-c e +d f +e \left (c +\frac {d}{x}\right )\right ) e}+\frac {-\frac {\sinIntegral \left (-\frac {d}{x}-c -\frac {-c e +d f}{e}\right ) \sin \left (\frac {-c e +d f}{e}\right )}{e}+\frac {\cosineIntegral \left (\frac {d}{x}+c +\frac {-c e +d f}{e}\right ) \cos \left (\frac {-c e +d f}{e}\right )}{e}}{e}\right )}{e}+\frac {c a}{2 \left (-c e +d f +e \left (c +\frac {d}{x}\right )\right )^{2} e}-c b \left (-\frac {\sin \left (c +\frac {d}{x}\right )}{2 \left (-c e +d f +e \left (c +\frac {d}{x}\right )\right )^{2} e}+\frac {-\frac {\cos \left (c +\frac {d}{x}\right )}{\left (-c e +d f +e \left (c +\frac {d}{x}\right )\right ) e}-\frac {-\frac {\sinIntegral \left (-\frac {d}{x}-c -\frac {-c e +d f}{e}\right ) \cos \left (\frac {-c e +d f}{e}\right )}{e}-\frac {\cosineIntegral \left (\frac {d}{x}+c +\frac {-c e +d f}{e}\right ) \sin \left (\frac {-c e +d f}{e}\right )}{e}}{e}}{2 e}\right )\right )\) | \(542\) |
default | \(-d \left (-\frac {a}{e^{2} \left (-c e +d f +e \left (c +\frac {d}{x}\right )\right )}-\frac {\left (c e -d f \right ) a}{2 e^{2} \left (-c e +d f +e \left (c +\frac {d}{x}\right )\right )^{2}}+\frac {\left (c e -d f \right ) b \left (-\frac {\sin \left (c +\frac {d}{x}\right )}{2 \left (-c e +d f +e \left (c +\frac {d}{x}\right )\right )^{2} e}+\frac {-\frac {\cos \left (c +\frac {d}{x}\right )}{\left (-c e +d f +e \left (c +\frac {d}{x}\right )\right ) e}-\frac {-\frac {\sinIntegral \left (-\frac {d}{x}-c -\frac {-c e +d f}{e}\right ) \cos \left (\frac {-c e +d f}{e}\right )}{e}-\frac {\cosineIntegral \left (\frac {d}{x}+c +\frac {-c e +d f}{e}\right ) \sin \left (\frac {-c e +d f}{e}\right )}{e}}{e}}{2 e}\right )}{e}+\frac {b \left (-\frac {\sin \left (c +\frac {d}{x}\right )}{\left (-c e +d f +e \left (c +\frac {d}{x}\right )\right ) e}+\frac {-\frac {\sinIntegral \left (-\frac {d}{x}-c -\frac {-c e +d f}{e}\right ) \sin \left (\frac {-c e +d f}{e}\right )}{e}+\frac {\cosineIntegral \left (\frac {d}{x}+c +\frac {-c e +d f}{e}\right ) \cos \left (\frac {-c e +d f}{e}\right )}{e}}{e}\right )}{e}+\frac {c a}{2 \left (-c e +d f +e \left (c +\frac {d}{x}\right )\right )^{2} e}-c b \left (-\frac {\sin \left (c +\frac {d}{x}\right )}{2 \left (-c e +d f +e \left (c +\frac {d}{x}\right )\right )^{2} e}+\frac {-\frac {\cos \left (c +\frac {d}{x}\right )}{\left (-c e +d f +e \left (c +\frac {d}{x}\right )\right ) e}-\frac {-\frac {\sinIntegral \left (-\frac {d}{x}-c -\frac {-c e +d f}{e}\right ) \cos \left (\frac {-c e +d f}{e}\right )}{e}-\frac {\cosineIntegral \left (\frac {d}{x}+c +\frac {-c e +d f}{e}\right ) \sin \left (\frac {-c e +d f}{e}\right )}{e}}{e}}{2 e}\right )\right )\) | \(542\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.39, size = 419, normalized size = 1.80 \begin {gather*} -\frac {2 \, {\left ({\left (b d f^{3} x^{2} e + 2 \, b d f^{2} x e^{2} + b d f e^{3}\right )} \operatorname {Ci}\left (\frac {{\left (d f x + d e\right )} e^{\left (-1\right )}}{x}\right ) + {\left (b d f^{3} x^{2} e + 2 \, b d f^{2} x e^{2} + b d f e^{3}\right )} \operatorname {Ci}\left (-\frac {{\left (d f x + d e\right )} e^{\left (-1\right )}}{x}\right ) + {\left (b d^{2} f^{4} x^{2} + 2 \, b d^{2} f^{3} x e + b d^{2} f^{2} e^{2}\right )} \operatorname {Si}\left (\frac {{\left (d f x + d e\right )} e^{\left (-1\right )}}{x}\right )\right )} \cos \left (-{\left (d f - c e\right )} e^{\left (-1\right )}\right ) + 2 \, {\left (b d f^{3} x^{2} e + b d f^{2} x e^{2}\right )} \cos \left (\frac {c x + d}{x}\right ) + 2 \, a e^{4} + {\left ({\left (b d^{2} f^{4} x^{2} + 2 \, b d^{2} f^{3} x e + b d^{2} f^{2} e^{2}\right )} \operatorname {Ci}\left (\frac {{\left (d f x + d e\right )} e^{\left (-1\right )}}{x}\right ) + {\left (b d^{2} f^{4} x^{2} + 2 \, b d^{2} f^{3} x e + b d^{2} f^{2} e^{2}\right )} \operatorname {Ci}\left (-\frac {{\left (d f x + d e\right )} e^{\left (-1\right )}}{x}\right ) - 4 \, {\left (b d f^{3} x^{2} e + 2 \, b d f^{2} x e^{2} + b d f e^{3}\right )} \operatorname {Si}\left (\frac {{\left (d f x + d e\right )} e^{\left (-1\right )}}{x}\right )\right )} \sin \left (-{\left (d f - c e\right )} e^{\left (-1\right )}\right ) - 2 \, {\left (b f^{2} x^{2} e^{2} + 2 \, b f x e^{3}\right )} \sin \left (\frac {c x + d}{x}\right )}{4 \, {\left (f^{3} x^{2} e^{4} + 2 \, f^{2} x e^{5} + f e^{6}\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {a + b \sin {\left (c + \frac {d}{x} \right )}}{\left (e + f x\right )^{3}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 1502 vs.
\(2 (211) = 422\).
time = 7.65, size = 1502, normalized size = 6.45 \begin {gather*} \text {Too large to display} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {a+b\,\sin \left (c+\frac {d}{x}\right )}{{\left (e+f\,x\right )}^3} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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